![]() Graphic by Keith Ohlfs |
|
Problem 1 Notes, Hints, Suggestions
public boolean isBagelInFront () {
if (isFacingWall()) {
return false;
} else {
brushUp(); // don't change the state of the environment during inquiry
forward();
boolean result = isOverBagel();
backward();
brushDown(); // return to original state before inquiry
return result;
}
}
You might also want methods that check for a bagel to the left or right of a buggle.
tick method takes less than 20 lines,
much of which is whitespace, comments, and method headers.
public void setup() {
setDimensions(columns,rows);
}